Lambda Calculus let explanation needed

后端 未结 0 1402
眼角桃花
眼角桃花 2021-01-30 08:04

In this treatment of let a lambda calculus version of let is given

(\\f.z)(\\x.y)

with the words

f

相关标签:
回答
  • 消灭零回复
提交回复
热议问题