Using ruby, is it possible to make an array of each letter in the alphabet and 0-9 easily?
Try this:
alphabet_array = [*'a'..'z', *'A'..'Z', *'0'..'9']
Or as string:
alphabet_string = alphabet_array.join
for letters or numbers you can form ranges and iterate over them. try this to get a general idea:
("a".."z").each { |letter| p letter }
to get an array out of it, just try the following:
("a".."z").to_a
[*('a'..'z'), *('0'..'9')] # doesn't work in Ruby 1.8
or
('a'..'z').to_a + ('0'..'9').to_a # works in 1.8 and 1.9
or
(0...36).map{ |i| i.to_s 36 }
(the Integer#to_s method converts a number to a string representing it in a desired numeral system)
You can just do this:
("0".."Z").map { |i| i }
You can also do it this way:
'a'.upto('z').to_a + 0.upto(9).to_a
letters = *('a'..'z')
=> ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z"]