MySQL - How to SELECT based on value of another SELECT

Question

I have a table that looks something like this:

Name    Year   Value
 A      2000     5
 A      2001     3
 A      2002     7
 A      2003     1
 B      2000              


        

Answer 1

SELECT x.name, x.summary, (x.summary / COUNT(*)) as percents_of_total
FROM tbl t
INNER JOIN 
(SELECT name, SUM(value) as summary
FROM tbl
WHERE year BETWEEN 2000 AND 2001
GROUP BY name) x ON x.name = t.name
GROUP BY x.name, x.summary

Answer 2

If you want to SELECT based on the value of another SELECT, then you probably want a "subselect":

http://beginner-sql-tutorial.com/sql-subquery.htm

For example, (from the link above):

1. You want the first and last names from table "student_details" ...

2. But you only want this information for those students in "science" class:

   SELECT id, first_name
   FROM student_details
   WHERE first_name IN (SELECT first_name
   FROM student_details
   WHERE subject= 'Science'); 
   

Frankly, I'm not sure this is what you're looking for or not ... but I hope it helps ... at least a little...

IMHO...

Answer 3

You can calculate the total (and from that the desired percentage) by using a subquery in the FROM clause:

SELECT Name,
       SUM(Value) AS "SUM(VALUE)",
       SUM(Value) / totals.total AS "% of Total"
FROM   table1,
       (
           SELECT Name,
                  SUM(Value) AS total
           FROM   table1
           GROUP BY Name
       ) AS totals
WHERE  table1.Name = totals.Name
AND    Year BETWEEN 2000 AND 2001
GROUP BY Name;

Note that the subquery does not have the WHERE clause filtering the years.