python: get directory two levels up

Question

Ok...I dont know where module x is, but I know that I need to get the path to the directory two levels up.

So, is there a more elegant way to do:

Answer 1

You can use pathlib. Unfortunately this is only available in the stdlib for Python 3.4. If you have an older version you'll have to install a copy from PyPI here. This should be easy to do using pip.

from pathlib import Path

p = Path(__file__).parents[1]

print(p)
# /absolute/path/to/two/levels/up

This uses the parents sequence which provides access to the parent directories and chooses the 2nd one up.

Note that p in this case will be some form of Path object, with their own methods. If you need the paths as string then you can call str on them.

Answer 2

Assuming you want to access folder named xzy two folders up your python file. This works for me and platform independent.

".././xyz"

Answer 3

Very easy:

Here is what you want:

import os.path as path

two_up =  path.abspath(path.join(__file__ ,"../.."))

Answer 4

For getting the directory 2 levels up:

 import os.path as path
 two_up = path.abspath(path.join(os.getcwd(),"../.."))

Answer 5

(pathlib.Path('../../') ).resolve()

Answer 6

I have found that the following works well in 2.7.x

import os
two_up = os.path.normpath(os.path.join(__file__,'../'))