I have a folder in my server which contains some files. These are automated that means everyday we get new files automatically which will overwrite the old ones. So want to take
You can be used this step is very useful:
for i in `ls -l folder1 | grep -v total | awk '{print $ ( ? )}'`
do
cd folder1
cp $i folder2/$i.`date +%m%d%Y`
done
path_src=./folder1
path_dst=./folder2
date=$(date +"%m%d%y")
for file_src in $path_src/*; do
file_dst="$path_dst/$(basename $file_src | \
sed "s/^\(.*\)\.\(.*\)/\1$date.\2/")"
echo mv "$file_src" "$file_dst"
done
You could use a script like the below. You would just need to change the date options to match the format you wanted.
#!/bin/bash
for i in `ls -l /directroy`
do
cp $i /newDirectory/$i.`date +%m%d%Y`
done
There is a proper way to split the filename and the extension: Extract filename and extension in Bash
You can apply it like this:
date=$(date +"%m%d%y")
for FILE in folder1/*.csv
do
bname=$(basename "$FILE")
extension="${bname##*.}"
filenamewoext="${bname%.*}"
newfilename="${filenamewoext}${date}.${extension}
cp folder1/${FILE} folder2/${newfilename}
done
cp --archive home/webapps/project1/folder1/{aaa,bbb,ccc,ffffd}.csv home/webapps/project1/folder2
rename 's/\.csv$/'$(date +%m%d%Y).csv'/' home/webapps/project1/folder2/{aaa,bbb,ccc,ffffd}.csv
Explanation:
--archive
ensures that the files are copied with the same ownership and permissions.foo{bar,baz}
is expanded into foobar foobaz
.rename
is a commonly available program to do exactly this kind of substitution.PS: don't use ls for this.
In bash
, provided you files names have no spaces:
cd /home/webapps/project1/folder1
for f in *.csv
do
cp -v "$f" /home/webapps/project1/folder2/"${f%.csv}"$(date +%m%d%y).csv
done