Do we have a way to view assembly and c code both using gdb.
disassemble function_name shows only assembly, I was trying to find a way to easliy map c code to assembly.
You can run gdb in Text User Interface (TUI) mode:
gdb -tui <your-binary>
(gdb) b main
(gdb) r
(gdb) layout split
The layout split
command divides the window into two parts - one of them displaying the source code, the other one the corresponding assembly.
A few others tricks:
If you do not want to use the TUI mode (e.g. your terminal does not like it), you can always do:
x /12i $pc
which means print 12 instructions from current program counter address - this also works with the tricks above (demangling, stepping instructions, etc.).
The "x /12i $pc" trick works in both gdb and cgdb, whereas "layout split" only works in gdb.
Enjoy :)
Try disassemble /m
.
Refer to http://sourceware.org/gdb/current/onlinedocs/gdb/Machine-Code.html#Machine-Code
The format is similar to that of objdump -S
, and intermixes source with disassembly. Sample output excerpt:
10 int i = 0;
=> 0x0000000000400536 <+9>: movl $0x0,-0x14(%rbp)
11 while (1) {
12 i++;
0x000000000040053d <+16>: addl $0x1,-0x14(%rbp)
For your purpose, try
objdump -S <your_object_file>
from man objdump:
-S
--source
Display source code intermixed with disassembly, if possible.
Implies -d.