Jquery - How to get the style display attribute “none / block”

Question

Is there a way to get the style: display attribute which would have either none or block?

DIV :

        
                      

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Answer 1

this is the correct answer

$('#theid').css('display') == 'none'

You can also use following line to find if it is display block or none

$('.deal_details').is(':visible')

Answer 2

//animated show/hide

function showHide(id) {
      var hidden= ("none" == $( "#".concat(id) ).css("display"));
      if(hidden){
          $( "#".concat(id) ).show(1000);
      }else{
          $("#".concat(id) ).hide(1000);
      }
  }

Answer 3

My answer

/**
 * Display form to reply comment
 */
function displayReplyForm(commentId) {
    var replyForm = $('#reply-form-' + commentId);
    if (replyForm.css('display') == 'block') { // Current display
        replyForm.css('display', 'none');
    } else { // Hide reply form
        replyForm.css('display', 'block');
    }
}

Answer 4

You could try:

$j('div.contextualError.ckgcellphone').css('display')

Answer 5

If you're using jquery 1.6.2 you only need to code

$('#theid').css('display')

for example:

if($('#theid').css('display') == 'none'){ 
   $('#theid').show('slow'); 
} else { 
   $('#theid').hide('slow'); 
}