How to allow users to change their own passwords in Django?

Question

Can any one point me to code where users can change their own passwords in Django?

Answer 1

Its without need to go to shell enter passwd and reenter passwd

 python manage.py changepassword <username> 
  or
/manage.py changepassword <username>

Using shell

python manage.py shell
from django.contrib.auth.models import User
users=User.objects.filter(email='<user_email>') 
  #you can user username or etc to get users query set
  #you can also use get method to get users
user=users[0]
user.set_password('__enter passwd__')
user.save()
exit()

Answer 2

Once the url pattern is added as shown in Ciro Santilli's answer, a quick way to allow users to change passwords is to give them "staff access" for the admin functions. If you don't add them to any groups or give them special permissions, they can still change their password by going to the example.com/admin page. The staff access lets them go to the page even if it is blank; in the upper right corner they can click "change password" and use the admin funtionality.

Answer 3

You can also just use the django.contrib.auth.views.password_change view in your URLconf. It uses a default form and template; supplying your own is optional.

Answer 4

urls.py:

urlpatterns = [
    url(r'^accounts/', include('django.contrib.auth.urls')),

Template:

<a href="{% url 'password_change' %}">{% trans "Change password" %}</a>

Documented at: https://docs.djangoproject.com/en/1.9/topics/auth/default/#using-the-views

Answer 5

Per the documentation, use:

from django.contrib.auth.hashers import makepassword

The main reason to do this is that Django uses hashed passwords to store in the database.

password=make_password(password,hasher='default')
obj=User.objects.filter(empid=emp_id).update(username=username,password=password)

I used this technique for the custom user model which is derived from the AbstractUser model. I am sorry if I technically misspelled the class and subclass, but the technique worked well.

Answer 6

This tutorial shows how to do it with function based views:

View file:

from django.contrib import messages
from django.contrib.auth import update_session_auth_hash
from django.contrib.auth.forms import PasswordChangeForm
from django.shortcuts import render, redirect

def change_password(request):
    if request.method == 'POST':
        form = PasswordChangeForm(request.user, request.POST)
        if form.is_valid():
            user = form.save()
            update_session_auth_hash(request, user)  # Important!
            messages.success(request, 'Your password was successfully updated!')
            return redirect('change_password')
        else:
            messages.error(request, 'Please correct the error below.')
    else:
        form = PasswordChangeForm(request.user)
    return render(request, 'accounts/change_password.html', {
        'form': form
    })

Url file:

from django.conf.urls import url
from myproject.accounts import views

urlpatterns = [
    url(r'^password/$', views.change_password, name='change_password'),
]

And finally, the template:

<form method="post">
  {% csrf_token %}
  {{ form }}
  <button type="submit">Save changes</button>
</form>