How to initialize an array in one step using Ruby?

Question

I initialize an array this way:

array = Array.new
array << \'1\' << \'2\' << \'3\'

Is it possible to do that in one s

Answer 1

To create such an array you could do:

array = ['1', '2', '3']

Answer 2

To prove There's More Than One Six Ways To Do It:

plus_1 = 1.method(:+)
Array.new(3, &plus_1) # => [1, 2, 3]

If 1.method(:+) wasn't possible, you could also do

plus_1 = Proc.new {|n| n + 1}
Array.new(3, &plus_1) # => [1, 2, 3]

Sure, it's overkill in this scenario, but if plus_1 was a really long expression, you might want to put it on a separate line from the array creation.

Answer 3

Oneliner:

array = [] << 1 << 2 << 3   #this is for fixnums.

or

 a = %w| 1 2 3 4 5 |

or

 a = [*'1'..'3']

or

 a = Array.new(3, '1')

or

 a = Array[*'1'..'3']

Answer 4

Along with the above answers , you can do this too

    =>  [*'1'.."5"]   #remember *
    => ["1", "2", "3", "4", "5"]

Answer 5

You can do

array = ['1', '2', '3']

As others have noted, you can also initialize an array with %w notation like so:

array = %w(1 2 3)

or

array = %w[1 2 3]

Please note that in both cases each element is a string, rather than an integer. So if you want an array whose elements are integers, you should not wrap each element with apostrophes:

array_of_integers = [1, 2, 3]

Also, you don't need to put comma in between the elements (which is necessary when creating an array without this %w notation). If you do this (which I often did by mistake), as in:

wrong_array = %w(1, 2, 3)

its elements will be three strings ---- "1,", "2,", "3". So if you do:

puts wrong_array

the output will be:

1,
2,
3
=>nil

which is not what we want here.

Hope this helps to clarify the point!

Answer 6

You can initialize an array in one step by writing the elements in [] like this:

array = ['1', '2', '3']