How do I activate a Spring Boot profile when running from IntelliJ?

Question

I have 5 environments:

 - local (my development machine)
 - dev
 - qc
 - uat
 - live
 - staging

I want different application properties to be u

Answer 1

I ended up adding the following to my build.gradle:

bootRun {
  environment SPRING_PROFILES_ACTIVE: environment.SPRING_PROFILES_ACTIVE ?: "local"
}

test {
  environment SPRING_PROFILES_ACTIVE: environment.SPRING_PROFILES_ACTIVE ?: "test"
}

So now when running bootRun from IntelliJ, it defaults to the "local" profile.

On our other environments, we will simply set the 'SPRING_PROFILES_ACTIVE' environment variable in Tomcat.

I got this from a comment found here: https://github.com/spring-projects/spring-boot/pull/592

Answer 2

I added -Dspring.profiles.active=test to VM Options and then re-ran that configuration. It worked perfectly.

This can be set by

• Choosing Run | Edit Configurations...
• Go to the Configuration tab
• Expand the Environment section to reveal VM options

Answer 3

Try add this command in your build.gradle

So for running configure that shape:

Answer 4

A probable cause could be that you do not pass the command line parameters into the applications main method. I made the same mistake some weeks ago.

public static final void main(String... args) {
    SpringApplication.run(Application.class, args);
}

Answer 5

Try this. Edit your build.gradle file as followed.

ext { profile = project.hasProperty('profile') ? project['profile'] : 'local' }

Answer 6

So for resuming...

If you have the IntelliJ Ultimate the correct answer is the one provided by Daniel Bubenheim

But if you don't, create in Run->Edit Configurations and in Configuration tab add the next Environment variable:

SPRING_PROFILES_ACTIVE=profilename

And to execute the jar do:

java -jar -Dspring.profiles.active=profilename XXX.jar