How do I read the first line of a file using cat
?
You dont need any external command if you have bash v4+
< file.txt mapfile -n1 && echo ${MAPFILE[0]}
or if you really want cat
cat file.txt | mapfile -n1 && echo ${MAPFILE[0]}
:)
I'm surprised that this question has been around as long as it has, and nobody has provided the pre-mapfile built-in approach yet.
IFS= read -r first_line <file
...puts the first line of the file in the variable expanded by "$first_line"
, easy as that.
Moreover, because read
is built into bash and this usage requires no subshell, it's significantly more efficient than approaches involving subprocesses such as head
or awk
.
There are many different ways:
sed -n 1p file
head -n 1 file
awk 'NR==1' file
There is plenty of good answer to this question. Just gonna drop another one into the basket if you wish to do it with lolcat
lolcat FileName.csv | head -n 1
Adding one more obnoxious alternative to the list:
perl -pe'$.<=1||last' file
# or
perl -pe'$.<=1||last' < file
# or
cat file | perl -pe'$.<=1||last'
This may not be possible with cat
. Is there a reason you have to use cat
?
If you simply need to do it with a bash command, this should work for you:
head -n 1 file.txt