How would you get only the first line of a file as a string with Python?
Lots of other answers here, but to answer precisely the question you asked (before @MarkAmery went and edited the original question and changed the meaning):
>>> f = open('myfile.txt')
>>> data = f.read()
>>> # I'm assuming you had the above before asking the question
>>> first_line = data.split('\n', 1)[0]
In other words, if you've already read in the file (as you said), and have a big block of data in memory, then to get the first line from it efficiently, do a split() on the newline character, once only, and take the first element from the resulting list.
Note that this does not include the \n
character at the end of the line, but I'm assuming you don't want it anyway (and a single-line file may not even have one). Also note that although it's pretty short and quick, it does make a copy of the data, so for a really large blob of memory you may not consider it "efficient". As always, it depends...
fline=open("myfile").readline().rstrip()
Use the .readline()
method (Python 2 docs, Python 3 docs):
with open('myfile.txt') as f:
first_line = f.readline()
Some notes:
f.readline()
will contain a trailing newline. You may wish to use f.readline().strip()
instead to remove the newline.with
statement automatically closes the file again when the block ends.with
statement only works in Python 2.5 and up, and in Python 2.5 you need to use from __future__ import with_statement
This should do it:
f = open('myfile.txt')
first = f.readline()
To go back to the beginning of an open file and then return the first line, do this:
my_file.seek(0)
first_line = my_file.readline()
f1 = open("input1.txt", "r")
print(f1.readline())