Facemash algorithm [closed]

Answer 1

I don't know what algorithm was actually used for the real-world site, but what they write on the window in the movie is based on the Elo rating system, which originated in the chess world and is now also used in many other games.

Answer 2

`I have designed the code in Perl all from google searching and it works.

Here's It

use strict;
use warnings;
use WWW::Mechanize;
use LWP::Simple;

sub images()
{
my $mech = WWW::Mechanize->new();
my ($site,$count,$file,$dir);
print "\t\t\tDesigned By NUMWARZ GAMING\n\n";
print "Enter the name of the site you want to search for images\t:\n";
$site = <STDIN>;

    print "Enter the folder where you want to save this\t:\n";

    $dir = <STDIN>;

    open my $doc, ">" , $dir."sitelist.txt";

    $mech->get( $site);

    my @links = $mech->images();

    $count = 0;

    for my $link ( @links ) 
    {
    $file = $dir.$count.".jpg";

    mirror($link->url,$file);

    print $file," : "$link->url,"\n";

    print $doc $link->url." ".$file."\n";

    $count+=1;
  }
  close $doc;
  exit;
  }

 images();

Answer 3

I recreated it aswell check it out. Not sure about php but the C# class is

http://lukedurrant.com/2010/11/c-elo-rating-class-used-on-facemash-as-seen-in-the-social-network-movie/

I used it on my

Facemash

Key press code is

$(document).keydown(function(event) {
    if (event.keyCode == 37) {
        //Voted Face 1
        Rate("face1", false);
    } 
    if(event.keyCode == 39) {
        //Voted Face 2
        Rate("face2", false);
    }

});

Answer 4

here is a clone of facemash available http://www.facemash.99k.org

Answer 5

UPDATE:

As I said in the comments, I've added this algerithm to my new website. At first it seemed to work perfectly. But after some weird inputs some strange result began to form.

While debugging I figured out what I was doing wrong. When getting the score for a "direct relationship" (used in the indirect relationship too) between 2 nodes I added the scores together. This was wrong, the score of a direct relationship should be expressed in -1 to +1, where:

-1 = lost everything 
+1 = won everything

So if A won 8 times to B, and B won 2 times to A the score should be:

(A wins) 8 + (B wins) 2 = (total matches)10
(delta of -1 and +1 =) 2 / (total matches)10 = (points per win) 0.2
Score of A vs B = (points per win) 0.2 * (wins) 8 - 1 = 0.6
Score of B vs A = (points per win) 0.2 * (wins) 2 - 1 = -0.4

Also I didn't mention this in the original explanation but it is all about triangles. So when we look at the indirect score, you don't need to go any further than 1 hop.

Answer 6

I've recreated it as well, but in a WordPress plugin

http://pofornot.com/

http://codecanyon.net/item/pics-mash-image-rating-tool/3256459?ref=mikemayhem3030