Array to Hash Ruby

Question

Okay so here\'s the deal, I\'ve been googling for ages to find a solution to this and while there are many out there, they don\'t seem to do the job I\'m looking for.

Ba

Answer 1

Just use Hash.[] with the values in the array. For example:

arr = [1,2,3,4]
Hash[*arr] #=> gives {1 => 2, 3 => 4}

Answer 2

Enumerator includes Enumerable. Since 2.1, Enumerable also has a method #to_h. That's why, we can write :-

a = ["item 1", "item 2", "item 3", "item 4"]
a.each_slice(2).to_h
# => {"item 1"=>"item 2", "item 3"=>"item 4"}

Because #each_slice without block gives us Enumerator, and as per the above explanation, we can call the #to_h method on the Enumerator object.

Answer 3

a = ["item 1", "item 2", "item 3", "item 4"]
Hash[ a.each_slice( 2 ).map { |e| e } ]

or, if you hate Hash[ ... ]:

a.each_slice( 2 ).each_with_object Hash.new do |(k, v), h| h[k] = v end

or, if you are a lazy fan of broken functional programming:

h = a.lazy.each_slice( 2 ).tap { |a|
  break Hash.new { |h, k| h[k] = a.find { |e, _| e == k }[1] }
}
#=> {}
h["item 1"] #=> "item 2"
h["item 3"] #=> "item 4"