zsh compinit: insecure directories

Question

What does it mean and how can I fix it?

zsh compinit: insecure directories, run compaudit for list.
Ignore insecure directories and continue [y] or abort compini         


        

Answer 1

I got the same warnings when I sudo -i starting a root shell, @chakrit's solution didn't work for me.

But I found -u switch of compinit works, e.g. in your .zshrc/zshenv or where you called compinit

compinit -u

NB: Not recommended for production system

See also http://zsh.sourceforge.net/Doc/Release/Completion-System.html#Initialization

Answer 2

on Mojave, this did the trick : sudo chmod go-w /usr/local/share

Answer 3

This was the only thing that worked for me from https://github.com/zsh-users/zsh-completions/issues/433#issuecomment-600582607. Thanks https://github.com/malaquiasdev!

  $ cd /usr/local/share/
  $ sudo chmod -R 755 zsh
  $ sudo chown -R root:staff zsh

Answer 4

This answer is mostly a reference for myself to use in the future, as most answers do not provide a full-fledged solution. Here it is:

First run:

compinit

For every single path that is printed run the following the commands:

sudo chown $(whoami) PATH_HERE

sudo chmod -R 755 PATH_HERE

Simple example, let's say one of the paths that gets printed after running compinit is "/usr/local/share/zsh". Then:

sudo chown $(whoami) /usr/local/share/zsh

sudo chmod -R 755 /usr/local/share/zsh

Answer 5

MAC OS X solution :

$ sudo chmod -R 755 /usr/local/share/zsh
$ sudo chown -R root:staff /usr/local/share/zsh

Also "user:staff = default root user on OSX.