Regex to match end-of-sentence markers [closed]

Answer 1

The below regex would match the non-word characters (except spaces) which must be followed by a space character or end of the line anchor. replaceAll function helps to remove all the matched characters.

String s = "Blah! blah? blah... blah blah!!";
System.out.println(s.replaceAll("[^\\w\\s]+(?=\\s|$)", ""));

Output:

Blah blah blah blah blah

If you want to remove only ?, ., ! characters which was present at the last in a word, you could try the below code.

String s = "This is the f!!rst sentence! Is this the second one? The third sentence is here... And the fourth one!!";
System.out.println(s.replaceAll("[!?.]+(?=\\s|$)", ""));

Output:

This is the f!!rst sentence Is this the second one The third sentence is here And the fourth one

Answer 2

You'd probably want to match anything (.*?) followed by the end of sentence followed by whitespace (\s+). Since !, ? and . are special characters, you'll need to excape them.

eg

Pattern pattern = Pattern.compile("(.*?)[\\!\\?\\.]\\s+");
Matcher matcher = pattern.matcher("one two. three! four five? ");
while (matcher.find()) {
   System.out.println(matcher.group(1));
}

prints

one two
three
four five

Answer 3

[!?.]+(?=$|\s)

Try this.You can add markers as needed.Replace by ``.

See demo.

http://regex101.com/r/lS5tT3/15