C++ program is giving a too many arguments warning

Question

I barely know what I\'m doing, I have this code where I try to solve some simple math:

 #include
 #include
 #include

        

Answer 1

Corrected code (fixes as pointed out in the comments):

#include<stdio.h>
//#include<conio.h> // You don't use anything from these headers (yet?)
//#include<stdlib.h>

//main()
int main() // main has to be defiend as an int function
{
    int n, sum = 0;
    printf("ENTER NUMBER:");
//  scanf("%i", n);
    scanf("%i", &n); // scanf need the ADDRRESS of variables
    while (n > 0)
    {
        sum += n;
        n--;
    }
//  printf("\n sum is:", sum);
    printf("\n sum is: %i", sum); // printf needs a format specifier for each variable
    return 0;
}

Answer 2

The compiler is warning you that you forgot to specify the field for sum in the format string. You probably wanted:

printf("\n sum is: %d",sum);

As above, it will not print the sum, and the sum value will not be used. Hence the warning.