C language What this code mean ? if(button & 1)==1 [closed]

Answer 1

The & operator is a bitwise AND, so this code checks whether the lowest bit in button is set.

Usually, one would compare to 0 in order to have a consistent style when looking at higher bits.

Answer 2

It checks whether lowest bit is set or not.. in other words, whether button is even or odd..

even this if(button & 1) wolud have done same.

Answer 3

This if performs a bitwise "and" of the value of button and 1 and then compares the result to 0. In essense the bitwise and will be 1 if and only if the last(least significant) bit of button is one which is also equivalent to button being odd.

So in short this if checks if button is odd.

Answer 4

The bitwise AND operator (&) compares each bit of the first operand to the corresponding bit of the second operand. If both bits are 1, the corresponding result bit is set to 1. Otherwise, the corresponding result bit is set to 0. So if (button & 1) is 1 then if(button & 1)==1 evaluates true otherwise evaluates to false.