Getting total value of an array with condition

Question

I need to get the total value of this array of all the numbers above or equal to 0. This is the array

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6         


        

Answer 1

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 

$total=0;
for($i =0 ; $i< count($aReeks) ; $i++)
{
if($aReeks[$i]>=0)
{
    $total+= $aReeks[$i];
}
}
echo $total ;
?>

Output

11859

Answer 2

Here's a quick way:

$total = array_sum(array_filter($aReeks, function($n) { return $n > 0; }));

• Filter the array for values greater than 0
• Sum that array

Oh I now see the "I have to do it with a for loop.", so this won't be accepted for your homework I imagine.

Answer 3

You are making 2 major mistakes one is in if condition which is $totaal < $aReeks[$y] you don't need this check at all. Secondly rather than summing up the value of each item to the total of all previous items... you are simply assigning the value to the $totaal variable inside the loop.

$aReeks = array(23,245,1,2,12,-10,46,6,66,9999,-55,348,56,6,66,983); 
$totaal = 0;
for($y=0; $y < count($aReeks); $y++)
{
    if($aReeks[$y] > 0)
        $totaal = $totaal + $aReeks[$y];
}