Why does the super() not showing error though not given in first line?

Question

Why does the super keyword not showing error though not given in first line

Answer 1

super(args...) is required for the constructor's at first line.

super.property can be used anywhere in the code

Answer 2

Then you might be making a method call and not Sayin super() inside constructor.. for instance..

class Superclass
{
public void f1(){

}
}

class Subclass extends Superclass
{
    Subclass()
    {
        System.out.println();
        super.f1();
    }
}

The above code works fine...

Answer 3

It does for me:

class Superclass
{
}

class Subclass extends Superclass
{
    Subclass()
    {
        System.out.println();
        super();
    }
}

Compiling gives an error of:

Test.java:10: call to super must be first statement in constructor
        super();
             ^
1 error

Please show a similar short but complete program with it not giving an error. Note that I'm assuming you really have got super(); rather than, say, super.foo(); which is just a call to the superclass implementation of foo(); and can appear anywhere in a method or constructor.