error while passing the value in python

Question

 def row_minimum(x,L):
  L=L
  if x==\'1\':
    row_minimum1=min(L[0],L[1],L[2],L[3],L[4])
    return row_minimum1
  elif x==\'2\':
    row_minimum2=min(L[5],L[6],L[7],L         


        

Answer 1

Your code has two nested definitions of user_input, so when you call it you get out the function definition instead of what it is supposed to return. Delete one of the def user_input(y): lines and fix your indentation and I bet it works.

Answer 2

You may want something like this:

def user_input(y):
    if y in ['1','2','3','A','B','C','D','E']:
        condition = False
    else:
        condition = True
        while condition == True:
            z=input("Enter a row (as a number) or a column (as and uppercase letter):")
            if z in ['1','2','3','A','B','C','D','E']:
                condition = False
        return z


print user_input('1')
print user_input('4')

Edit

If you get something like <function user_input at 0x0000000002CB1128>, its because you are printing the function. (And it's not an error)

print user_input # This is not wath you want

This instead is what you want:

print user_input(...) # Where ... is the parameter you are giving to your function