I have an array of objects that looks like the image below. Is there a way by which I can have an array that contains unique objects with respect to id ? We can
To get an array of "unique" objects(with last index within the list) for your particular case use the following approach (Array.forEach
, Array.map
and Object.keys
functions):
// exemplary array of objects (id 'WAew111' occurs twice)
var arr = [{id: 'WAew111', text: "first"}, {id: 'WAew222', text: "b"}, {id: 'WAew111', text: "last"}, {id: 'WAew33', text: "c"}],
obj = {}, new_arr = [];
// in the end the last unique object will be considered
arr.forEach(function(v){
obj[v['id']] = v;
});
new_arr = Object.keys(obj).map(function(id) { return obj[id]; });
console.log(JSON.stringify(new_arr, 0, 4));
The output:
[
{
"id": "WAew111",
"text": "last"
},
{
"id": "WAew222",
"text": "b"
},
{
"id": "WAew33",
"text": "c"
}
]
The best way to do this is to modify your data structure into an object itself where each key is one of the IDs:
{
"WadWA7WA6WAaWAdWA...": {
"text": "birla"
},
"WadWA...": {
"test": "ab"
}
}
and so forth. If the data comes from a source formatted that way, you can always map the array of results to this format.
You could create a hash using the id as the key and keeping the value as the entire object:
var myHash = new Object();
var i;
for(i = 0; i < yourArray.length; i++) {
var yourObjId = yourArray[i][id];
myHash[yourObjId] = yourArray[i];
}
You would be left with a hash myHash
containing objects with unique id's (and only the last object of duplicates would be stored)
Try this: just add to a new object using id as the key
var arr = [{id:'123', text: 'a'}, {id:'234', text: 'b'}, {id:'123', text: 'c'}];
var map = new Object();
for(var i in arr){ map[arr[i].id] = arr[i]; }
var newArr = [];
for(var i in map){ newArr.push(map[i]); }
newArr shall contain the 2nd and 3rd object.