I have come across a very strange problem. I have tried to find its solution but in vain. My problem is that I want to create a random number between 1-45 and I don\'t want tha
Random selection, by definition, will repeat randomly.
However, you can build an array containing each of your numbers and then shuffle the array, producing a random order of numbers without repetition.
var nums = [], i;
for( i=1; i<=45; i++) nums.push(i);
nums.sort(function(a,b) {return Math.random()-0.5;});
alert(nums.join(","));
This is Working code..
Random rd =new Random();
int n = rd.Next(1,45);
What you really want is to create a set of numbers in a given range and to randomly remove one of the numbers until the set is empty.
Here is a function which generates another function which does exactly that:
function generateRandomRangeSet(beg, end) {
var numbers = []; // Create an array in range [beg, end].
for (var i=beg; i<=end; i++) { numbers.push(i); }
return function() {
if (numbers.length < 1) { throw new Error('no more numbers'); }
var i=Math.floor(Math.random()*numbers.length), number=numbers[i];
numbers.splice(i, 1); // Return and remove a random element of the array.
return number;
}
}
var r = generateRandomRangeSet(1, 45);
r(); // => 9
r(); // => 24
r(); // => 7 ... for each number [1, 45] then ...
r(); // Error: no more numbers
This is working
function getRandomInt(min, max) {
return Math.floor(Math.random() * (max - min)) + min;
}