String length using pointers

Question

I was looking up some code tricks. I found one that I get the basics but I don\'t understand why it exits. It has to do with a string pointer in a while loop. Usually I don\'

Answer 1

while(*(s+c)) returns false when the null character is encountered and breaks the loop

Answer 2

int lungh(char *p){
    char *r = p;
    while(*p++!='\0'){}
    return p-r;
}

Answer 3

A string is an arrary of chars, of which the very last one is the terminating character - \0. The evaluation of while checks every char starting at position indcitated by pointer s, then shifting it to the next char (next array entry) by adding c to the start address. Once \0 - the terminating character - is reached the loop breaks.