Regex matching left single quotation outside the double quotations

Question

Note :

left double quotation (\") = &ldquo

right double quotation (\") = &rdquo

left single quotation (\') = &lsquo

My current regex

Answer 1

Use ASCII escape sequence to tell the regex which characters are you referring to.

• \x93 - Refers to &ldquo
• \x94 - Refers to &rdquo

So the regex you need is: [\x93]*[^x94]

Or if your you know what characters your string consists of, then: [A-Za-z0-9\x93]*[^x94], and so on. Add more characters as per your need.

Answer 2

this is the right regex that I am looking at :

(?<!.*&ldquo;)&lsquo;(?!.*&rdquo;)

Thanks!

Answer 3

If I understood ur question..This may be what you want

(?<!&ldquo.*?)&lsquo(?!&rdquo)