Assign variables and display results

Question

i get a T_ECHO unexpected error . what is the right way of accomplishing the above task?

Answer 1

In order for you to catch any data from the function get_option you most return it from within the function itself:

<?php
function get_option($var){
    return $var; 
}

$num_posts = get_option($shortname.'_num_posts');

 //outputs what ever was returned from the function
 echo $num_posts;

?>

Answer 2

What you are trying to do? If you want print, the code is:

<?php 
$somevariable = $anothervar;
?>

If you want to assign the value of the another var, the code is:

<?php 
echo $anothervar;
$somevariable = $anothervar;
?>

Answer 3

It should just be

<?php $somevariable = $anothervar; ?>

Answer 4

I don't know what you are trying to do. echo is a language construct, so returns nothing, so its return value cannot be assigned.

If you want to echo a value and assign it to another variable, it is best (most legible) to do it in two statements:

<?php

echo $anothervar;
$somevariable = $anothervar;

?>