Dropdown List from MySQL Column using mysqli [closed]

Answer 1

If you inicialized an object, then you should continue using mysqli as object.

There is no need to use prepared statements, but it isn't wrong.

<?php
include ("connect.php");

$db = new mysqli('localhost', $dbuser, $dbpass, $dbnam);
?>
<div class="label">Select Name:</div>
<select name="names">
<option value = "">---Select---</option>
<?php
$stmt = $db->prepare("SELECT `Name` FROM `Users`");
$stmt->execute();
$stmt->bind_result($name);
while ($stmt->fetch()){
    echo "<option value='$name'></option>";
}
$stmt->close();
?>
</select> 

Answer 2

The reason your select doesn't get populated is because the mysqli_query doesn't get a connection supplied.

Change:

$db = mysqli_query($queryusers);

Into:

$db = mysqli_query($db, $queryusers);

Also add the name between (else you get a list with no text):

while ( $d=mysqli_fetch_assoc($db)) {
  echo "<option value='{".$d['Name']."}'>".$d['Name']."</option>";
}

Hope this helped you out!