matlab constant anonymous function returns only one value instead of an array

Question

I\'ve been searching the net for a couple of mornings and found nothing, hope you can help.

I have an anonymous function like this

f = @(x,y) [sin(2*pi*x         


        

Answer 1

Defining an anonymous function f as

f = @(x,y) [0,1];

naturally returns [0,1] for any inputs x and y regardless of the length of those vectors.

This behavior puzzled me also until I realized that I expected f(a,b) to loop over a and b as if I had written

for inc = 1:length(a)
    f(a(inc), b(inc))
end

However, f(a,b) does not loop over the length of its inputs, so it merely returns [0,1] regardless of the length of a and b.

The desired behavior can be obtained by defining f as

g=@(x,y)[zeros(size(x)),ones(size(y))]

as Daniel stated in his answer.

Answer 2

You are defining a function f = @(x,y) [0, 1]; which has the input parameters x,y and the output [0,1]. What else do you expect to happen?

Update:

This should match your description:

g=@(x,y)[zeros(size(x)),ones(size(y))]
g(x',y')