Rock Paper Scissors - Python 3 - beginner

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南方客
南方客 2021-01-29 12:00

I\'m suppose to simulate a rock paper scissors game and this is what I have so far. It\'s not letting me input letters into the scoregame function. How can I fix th

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  • 2021-01-29 12:54

    You are using letters without quotes so its looking for a Variable called P but what you want is a String "P" so put the letters in quotes:

    if player1 == "P" and player2 == "S":
    
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  • 2021-01-29 13:03

    You need to test against strings; you are now testing against variable names:

    if player1 == 'R' and player2 == 'R':
    

    but you can simplify the case where both players picked the same option by testing if they are equal:

    if player1 == player2:
        scoregame = "It's a tie, nobody wins."
    

    Next, I'd use a mapping, a dictionary, to codify what beats what:

    beats = {'R': 'S', 'S': 'P', 'P': 'R'}
    
    if beats[player1] == player2:
        scoregame = "Player 1 wins."
    else:
        scoregame = "Player 2 wins."
    

    Now your game can be tested in just 2 tests. All put together:

    def scoregame(player1, player2):
        beats = {'R': 'S', 'S': 'P', 'P': 'R'}
        if player1 == player2:
            scoregame = "It's a tie, nobody wins."
        elif beats[player1] == player2:
            scoregame = "Player 1 wins."
        else:
            scoregame = "Player 2 wins."
        print(scoregame)
    
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