Python throws SyntaxError on this code [closed]

Answer 1

You are using input() instead of raw_input(); this interprets the input as a Python expression. It is easy to make that throw a SyntaxError exception:

>>> input("Enter a sentence: ")
Enter a sentence: The Quick Brown Fox
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<string>", line 1
    The Quick Brown Fox
            ^
SyntaxError: invalid syntax

Use raw_input() throughout instead:

dic[raw_input("Enter the value you want to store: ")]  = raw_input("Enter the access key of a value: ")

You probably want to turn these two questions around:

dic[raw_input("Enter the access key of a value: ")] = raw_input("Enter the value you want to store: ")

Python will ask for the value first. If you need to ask for the key first, store it in a separate variable first:

key = raw_input("Enter the access key of a value: ")
dic[key] = raw_input("Enter the value you want to store: ")

Answer 2

You had your lines the wrong way around, you need:

dic[raw_input("Enter the access key of a value: ")]  =  input("Enter the value you want to store: ")

Not

 dic[raw_input("Enter the value you want to store: ")]  = input("Enter the access key of a value: ")

So complete code would be:

while 1:
    dic = {} #empty dictionary which will be used for storing all the data
    dic[raw_input("Enter the access key of a value: ")]  =  input("Enter the value you want to store: ")
    ans = raw_input("Exit:e ; Store another variable : s; Acces a variable: a")
    if ans=="e":
        break; #exit the main loop
    elif ans == "s":
        continue;
    elif ans=="a":
        pass;