Test if a number is a multiple of another [closed]

Answer 1

//int g, c;
^^

Remove this line..

---

if (g%c==0){
        ^

You need to use == for checking equality.

---

You can actually do the below to cut down few lines as well..

public static boolean multiple(int g, int c) {
    return g%c == 0;
}

Answer 2

You're declaring the variables twice besides the = issue. Try this:

public static boolean multiple(int g, int c) {
    return g % c == 0;
}

Answer 3

There are too many errors in your method. It actually should be like this:

public static boolean multiple(int g, int c) {
    return g % c == 0;
}

Answer 4

First of all you don't need to declare g and c again in the function multiple (It is an error). Second, you didn't call the function at all, you just implemented it. And like other people answered, you need to have == instead of =.

public static void main(String[] args) {
    Scanner input = new Scanner (System.in);
    int a,b;
    System.out.println("enter the first number");
    a=input.nextInt(); 

    System.out.println("enter the first number");
    b=input.nextInt();

    boolean result = multiple(a,b);
    System.out.println(result);
}

public static boolean multiple (int g,int c){
    if (g%c==0){
        return true;
    }
    else
    {
        return false;
    }
}

Note that you can have a shorter version of multiple which have only one line: return g%c==0;