I want to compare two arrays with each other and see if there is a match, and if there is do something.
var answers = new Array(\"a\",\"b\",\"c\",\"d\", \"e\");
Try this code:
var a = [1,2,3,4]
, b = [1,3,5,7,9]
, c = ['a','b','c'];
function findDups( arr1, arr2 ) {
var arrs = [ arr1, arr2 ].sort(function( a,b ) {
return a.length > b.length;
});
return arrs[0].filter(function( v ) {
return ~arrs[1].indexOf( v );
});
}
function hasDups( arr1, arr2 ) {
return !!findDups( arr1, arr2 ).length;
}
console.log( findDups( a,b ) ); //=> [1, 3]
console.log( hasDups( a,c ) ); //=> false
Look this post, there is a code to compare disorder arrays: http://blog.maxcnunes.net/2012/08/10/comparacao-de-arrays-desordenados-javascript/
ps: the post is in portuguese, but you can use any translater to understand
Try using this:
for(var i = 0; i < answers.length; i++) {
for(var j = 0; j < correct.length; j++){
if (answers[i] === correct[j]){
console.log(answers[i]+ " is the correct answer")
break;
}
}
}