How to find Maximum value from 5 inputs by user? [closed]

Answer 1

Something like this should be fine, typing on mobile so excuse any syntax errors.

std::vector<int> user_inputs;

while (user_inputs.size() < 5)
{
    int user_arg = 0;

    std::cout << "Please enter number " << (user_inputs.size() + 1) << ": ";
    std::cin >> user_arg;

    user_inputs.push_back(user_arg);
}

std::sort(user_inputs.begin(), user_inputs.end());

std::cout << "Lowest value entered:" << user_inputs.front() << std::endl;
std::cout << "Highest value entered:" << user_inputs.back() << std::endl;

Answer 2

The Best Code I required Was

int a,b,c,d,e,max;
cin>>a;
max=a;
cin>>b;
if(b>max)
max=b;
cin>>c;
if(c>max)
max=c;
cin>>d;
if(d>max)
max=d;
cin>>e;
if(e>max)
max=e;

Answer 3

you can try this answer

for (i = 0; i < 5; i++) {
    cin>>a[i];
    }
    //Assume that a[0] is greatest value
    greatest = a[0];
    for (i = 0; i < 10; i++) {
      if (a[i] > greatest) {
         greatest = a[i];
    }
    }
      printf("Greatest of ten numbers is %d", greatest);
      return 0;

Answer 4

The most idiomatic way would be to use std::max_element which does exactly what the name suggests. For that, values would need to be in a container, for which e.g. a brace-initialized std::array (for a known number of 5 values), or a std::vector (for unknown-number of values) will do.

The next best way would be sorting as suggested by @Dilusha, but of course there's partial sorting and std::nth_element, which will do less work for the same net result (as you do not really need a sorted sequence, you only need one element in the right place -- a complete sort is thus "wasteful").

Or, you can of course just use a sequence of result = std::max(result, a [b c d... whatever]) which isn't very elegant, but will do the job just fine. Remember to initialize result to zero to begin with.