List comprehension not working [duplicate]

Answer 1

List comprehensions provide a concise way to create lists. Common applications are to make new lists where each element is the result of some operations applied to each member of another sequence or iterable, or to create a subsequence of those elements that satisfy a certain condition.

Maybe you can try this:

>>> new_list = []
>>> a = ['It', 'is', 'the', 'east', 'and', 'Juliet', 'is', 'the', 'sun']
>>> unused=[new_list.append(word) for word in a if word not in new_list]
>>> new_list
['It', 'is', 'the', 'east', 'and', 'Juliet', 'sun']
>>> unused
[None, None, None, None, None, None, None]

Notice:

append() returns None if the inserted operation is successful.

Another way, you can try to use set to remove duplicate item:

>>> a = ['It', 'is', 'the', 'east', 'and', 'Juliet', 'is', 'the', 'sun']
>>> list(set(a))
['and', 'sun', 'is', 'It', 'the', 'east', 'Juliet']

Answer 2

If you want a unique list of words, you can use set().

list(set(a))
# returns:
# ['It', 'is', 'east', 'and', 'the', 'sun', 'Juliet']

If the order is important, try:

new_list = []
for word in a:
    if not a in new_list:
        new_list.append(word)