Can we use PHP in Bash Script?

Question

I have a bash script abcd.sh

#!/bin/sh
for i in `seq 8`; do ssh w$i \'uptime;ps -elf|grep httpd|wc -l;free -m;mpstat\'; done &
pid=$!
sleep 1
ki         


        

Answer 1

Mmm, if you are using bash, you should maybe use a bash shebang on line 1 so people know you are expecting bash features to be available. And if you are using bash, you can use a bash sequence anyway:

#!/bin/bash
for i in {1..8}; do echo $i; done

Update 1

If the number of servers is obtained through PHP, you can do something like this:

numservers=$(php -r 'echo 8;')
for i in $(seq $numservers); do echo $i; done
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Update 2

Ok, you said the number of servers is dynamic, but then you say it is set in the script (which seems contradictory), but this is what you do:

numservers=10
for i in $(seq $numservers); do echo $i; done
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10

Answer 2

Why don't you write the entire shell script in PHP?

#!/usr/bin/php
<?php
for ($i = 0; $i < 8; $i++) {
    exec("ssh w$i 'uptime;ps -elf|grep httpd|wc -l;free -m;mpstat'");
}
?>

(code is untested, just an example)

Answer 3

It's not easy to understand what you want.

Maybe this helps. The script defines a var PHP_VAR in bash and use this var in PHP. Then we call a PHP code snippet an put the output in the shell var output. At last we output the var output (but you can do something else with it).

Attation: All the output from the PHP will be found in the var output.

#!/bin/bash

echo "I am a bash echo"

export PHP_VAR="I was in php"
# Here we start php and put the output in 'output'
output=$(php << EOF
   <?php \$inner_var = getenv("PHP_VAR");
   echo \$inner_var; ?>
EOF
)

# usage var 'output' with php output
echo "---$output---"