Does \w also match numbers?

Question

I would expect that this

var r = new RegExp(\'\\\\s\\\\@[0-9a-z]+\\\\s\', \'gi\');

applied to this string

1 @bar @foo2 * 112


        

Answer 1

"\w" Matches any word character (alphanumeric & underscore). Only matches low-ascii characters (no accented or non-roman characters). Equivalent to [A-Za-z0-9_] Best source to learn : www.regexr.com

Answer 2

Yes, \w does match latin numbers. \w == [A-Za-z0-9_]

Assuming you want to remove @fooX, you can use:

console.log("1 @bar @foo2 * 112".replace(/\s@\w+/g, ""));

Answer 3

I quickly rigged this up which should do what you want.

var string = "1 @bar @foo2 * 112";

var matches = string.replace(/\s@\w+/gi,"");

console.log(matches)

I could not reproduce your results with that regex, but I did find the final \s would stop the matching of @foo2.

var value = "1 @bar @foo2 * 112";
var matches = value.match(
     new RegExp("\\s\\@[0-9a-z]+\\s", "gi")
);
console.log(matches)

This is because the regex can not then match the space in front of @foo which is required as part of the match. I hope this code solves your problem.