Regex: match only once

Question

I\'ve got a string with multiple ip addresses together with some random stuff. For example like this one:

21/Jun/2018:01:15:38 +0000    188.79.169.152    157.52.         


        

Answer 1

You can use re.match which matches a ptrn from the beginning of a string So just by adding a .* to the start of your pattern, we can match everything from the beginning of the string to the first ip address

>>> import re
>>> s = "21/Jun/2018:01:15:38 +0000    188.79.169.152    157.52.69.50    443    -    -    GET / 157.52.69.30 157.52.69.10"
>>> 
>>> ptrn = r'.*?([0-9]+(?:\.[0-9]+){3})'
>>> re.match(ptrn, s).groups()[0]
'188.79.169.152'