I have a sentence \"no it\'s all right lag\" where I am trying to detected a pattern \"no lag\". My regex is no + (\\\\s\\\\w*?\\\\s?){1,3} + lag
. This fails. Howev
I think just no(.*)lag pattern will work. If I understood right.
You could create a new character class with the [] notation, instead of having \w you should use [\w'] making the entire regex "no(\s[\w']*?\s?){1,3}lag" as a Java String.
Also for developing regular expressions I would recommend this site: http://www.regexplanet.com/advanced/java/index.html