Sort a python list of strings with a numeric number

Question

I have a list of filenames called filelist

 In []: filelist
Out []: [\'C:\\\\Mon20412\\\\P-2NODE-RAID6-1BLACK-32k-100-segmented.xlsx\',
                 


        

Answer 1

Use a regex to parse out the number and use that as a sort key.

Quick and dirty:

import re

l = ['C:\\Mon20412\\P-2NODE-RAID6-1BLACK-32k-100-segmented.xlsx',
     'C:\\Mon25312\\P-2NODE-RAID6-13RED-32k-100-segmented.xlsx',
     'C:\\Mon20362\\P-2NODE-RAID6-2GREEN-32k-100-segmented.xlsx']

def get_sort_number(s):
    pattern = r'C:\\Mon\d+\\P-2NODE-RAID6-(\d+)'

    try:
        return int(re.match(pattern, s).group(1))
    except AttributeError:
        return 0

sorted(l, key=get_sort_number)

This gives

['C:\\Mon20412\\P-2NODE-RAID6-1BLACK-32k-100-segmented.xlsx',
 'C:\\Mon20362\\P-2NODE-RAID6-2GREEN-32k-100-segmented.xlsx',
 'C:\\Mon25312\\P-2NODE-RAID6-13RED-32k-100-segmented.xlsx']

All strings that cannot be matched by the regex would be at the beginning of the sorted list.

Answer 2

Find a good, reliable way to extract the number that you want. Then sort by that number, using the key argument. This seems to be reliable enough for your input, but it's not efficient.

a = ['C:\\Mon20412\\P-2NODE-RAID6-1BLACK-32k-100-segmented.xlsx',
    'C:\\Mon25312\\P-2NODE-RAID6-13RED-32k-100-segmented.xlsx',
    'C:\\Mon20362\\P-2NODE-RAID6-2GREEN-32k-100-segmented.xlsx']

def k(a):
    x = a.split("\\")[-1].split("-")[3]
    y = filter(lambda x: x in "0123456789", x)
    return int("".join(list(y)))


print(sorted(a, key=k))

output:

['C:\\Mon20412\\P-2NODE-RAID6-1BLACK-32k-100-segmented.xlsx', 
'C:\\Mon20362\\P-2NODE-RAID6-2GREEN-32k-100-segmented.xlsx',
'C:\\Mon25312\\P-2NODE-RAID6-13RED-32k-100-segmented.xlsx']

Answer 3

import re

f = lambda s: int(re.findall(r'.*RAID6-(\d+).*', s)[0])
sorted(l, key=f)