How can I remove values array based on array other [duplicate]

Answer 1

Use following working code -

let arrayOne = [1,2,3,4,5,6,7,8]
let arrayTwo = [1,2,4,5,6,7]
var result = [Int]()

for value in arrayOne
{
     if !arrayTwo.contains(value)
     {
         result.append(value)
     }
}

Answer 2

User Set for simple result

var arrayOne = [1,2,3,4,5,6,7,8]

var arrayTwo = [1,2,4,5,6,7]

let set1:Set<Int> = Set(arrayOne)
let set2:Set<Int> = Set(arrayTwo)

let set3 =  set1.symmetricDifference(set2)

Output :

{3, 8}

Answer 3

You can do with below options.

// Option 1 - Using Set's

let arrayOne : Set = [1,2,3,4,5,6,7,8]

let arrayTwo : Set = [1,2,4,5,6,7]

var result = arrayOne.symmetricDifference(arrayTwo)

print(result) // {3,8}

// Option 2 - Using Array

var result1 = [Int]()

for value in arrayOne
{
    if !arrayTwo.contains(value)
    {
        result1.append(value)
        }
    }

print(result1) // {3,8}

Answer 4

You can do it by converting them to Sets.

var arrayOne = [1,2,3,4,5,6,7,8]
var arrayTwo = [1,2,4,5,6,7]

let set1:Set<String> = Set(arrayOne)
let set2:Set<String> = Set(arrayTwo)

Use ExclusiveOr to do this.

    //Swift 2.0
    set1.exclusiveOr(array2) // result = {3,8}

   //Swift 3.0
   set1.symmetricDifference(set2) // result = {3,8}

This link might useful for you: Set operations (union, intersection) on Swift array? also possible Duplicate as @user3589771 said.