returning the list reversed

Question

i have this question:

Write a function reverse3(nums) that takes a list of ints of length 3 called nums and returns a new list with the elements in reve

Answer 1

reversed returns an iterator. If you want to get a list object, use list:

>>> def reverse3(nums):
...     return list(reversed(nums))
... 
>>> reverse3([4,5,6])
[6, 5, 4]

Answer 2

List has a built in reverse function

list.reverse()

so you could use

nums.reverse()

However, if you want to write your own function you would need to do a reverse iteration to another list.

Something like-

def revList(nums)
   i = len(mums) -1
   while i >= 0:
      revNums[i] = nums.pop()
      i = i - 1
   return(revNums)