How to read wrongly formatted string in csv properly?

Question

In csv, for a column there is ambiguity in string. Because of that, I\'m getting 6 values in list instead of 5 values as output.

Code:<

Answer 1

This is almost embarrassingly hacky, but seems to work at least on the sample input shown in your question. It works by post-processing each row read by the csvreader and tries to detect when they have been read incorrectly due to the bad formatting — and then corrects it.

import csv

def read_csv(filename):
    with open(filename, 'rb') as file:
        for row in csv.reader(file, skipinitialspace=True, quotechar=None):
            newrow = []
            use_a = True
            for a, b in zip(row, row[1:]):
                # Detect bad formatting.
                if (a.startswith('"') and not a.endswith('"')
                        and not b.startswith('"') and b.endswith('"')):
                    # Join misread field backs together.
                    newrow.append(', '.join((a,b)))
                    use_a = False
                else:
                    if use_a:
                        newrow.append(a)
                    else:
                        newrow.append(b)
                        use_a = True
            yield [field.replace('""', '"').strip('"') for field in newrow]

for row in read_csv('fmt_test2.csv'):
    print(row)

Output:

['1', '2', 'text1', 'Sample text "present" in csv, as this', '5']