How to add a new method called numberOfDigits() in java?

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面向向阳花
面向向阳花 2021-01-29 04:19

I have a program called public class ZeroCounter {. I want to add a new method to it called numberOfDigits() and add a line to test it in the main() method. How should I go abo

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  • 2021-01-29 04:38

    Try this method to count digits of an integer number:-

     public int numberOfZeros(int number){
        return ((int) Math.log10(number) + 1);
    }
    

    Or you can try this code

          //Declare input as scanner
            Scanner input = new Scanner(System.in);
    
            //Take input
             System.out.println("Enter Number :");
             no = input.nextInt();
             System.out.println("Enter digit :");
             digit = input.nextInt();
    
            //add while loop
            while(no>0)
            {
                m=no%10;
                if(m==digit)
                    oc++;
                no=no/10;
            }
    
            System.out.println("Digit occurred "+oc+" times");
    
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  • 2021-01-29 04:46
    public class ZeroCounter   {
      public static void main(String[] args) {
             System.out.println("Enter a nonnegative number:");
             Scanner keyboard = new Scanner(System.in);
             int number = keyboard.nextInt( ) ;
    
             System.out.println(number + " contains " + numberOfZeros(number) + " zeros.");
      } // End of main
    
      private static int numberOfZeros(int number) {
             int result = ///// calculation
             return result;
      }
    }
    

    You might want to read up a bit more on Java and how classes, methods and functions work first before going any further however.

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  • 2021-01-29 04:58

    It should be:

    public class ZeroCounter {
    
        public static int numberOfDigits(int number) {
            //- Implementation goes here.
        }
    
        public static void main(String[] args) {
            int number;
            //- Initialize number variable.
            System.out.println("numberOfDigits(" + number + ")=" + numberOfDigits(number));
        }
    }
    
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  • 2021-01-29 05:04

    Try this.... :)

    public class ZeroCounter {
    
        public static int numberOfDigits(int number) 
        {
            //return Integer.toString(number).length();
            return String.valueOf(number).length();
        }
    
        public static void main(String[] args)
        {
            int number;
            Scanner Keyboard=new Scanner(System.in);
            System.out.print("Enter the number: ");
            number=Keyboard.nextInt();
            System.out.println("numberOfDigits(" + number + ")=" + numberOfDigits(number));
        }
    }
    

    Updated Code..

    import java.util.*;
    public class ZeroCounter 
    {
    
    public static int numberOfDigits(int number,char d) 
    {           
        //to get a char array of digits of number
        char[] n=Integer.toString(number).toCharArray();
        int r=0;
        for(char x:n)
        {
            if(x==d)
                r++;
        }
        return r;
    }
    
    public static void main(String[] args)
    {
        int number;
        char digit;
        boolean flag=false;
        Scanner Keyboard=new Scanner(System.in);
        try{
        System.out.print("Enter the non-negative number: ");
        number=Keyboard.nextInt();
    
        //to check number is positive or not
        if(number<=-1)
        throw new Exception();
        System.out.println(number + " contains " + numberOfDigits(number,'0') + " zeros.");
        System.out.print("Enter the digit: ");
    
        //to take only one letter as input
        digit=Keyboard.next(".").charAt(0);
    
        //to check input is digit or not
        if(!Character.isDigit(digit))
        throw new Exception();
        System.out.println("Number of digits(" + digit + ")=" + numberOfDigits(number,digit));
        }
           //to catch all exceptions
        catch(Exception e)
        {  
            System.out.println("\n You have entered invalid input..");
        }
    }
    }
    
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