jq retain missing array objects from capturing group and update array

Question

Input

[{
        \"tags\": [{
                \"value\": \"domain:sourcing\"
            },
            {
                  


        

Answer 1

If the "value" part of the "tag:value" strings might contain a colon (":"), then using split becomes unnecessarily tricky (and maybe even inefficient), so it might be easier to use capture, perhaps along the lines suggested by @RomanPerekhrest:

{domain:"-", apiname:"-"} as $default
| map([.tags[].value
       | capture("(?<k>[^:]*):(?<v>.*)")
       | {(.k): .v} ]
      | add
      | $default + .)

Answer 2

jq solution:

jq '{domain: "-", apiname: "-"} as $o 
    | map([.tags[] | .value | split(":") | {(.[0]) : .[1]}] | add | $o + .)' input.json

• {domain: "-", apiname: "-"} as $o - used as a template object

The output:

[
  {
    "domain": "sourcing",
    "apiname": "src1"
  },
  {
    "domain": "-",
    "apiname": "fin1"
  },
  {
    "domain": "fin1",
    "apiname": "-"
  }
]

Answer 3

Here's another approach. This assumes your tags array will only contain the names you expect.

map(
    reduce (.tags[].value | split(":")) as [$k,$v] (
        {domain:"-",apiname:"-"};
        .[$k] = $v
    )
)

---

For a more general solution that doesn't assume fixed names and just flattens the tags, I'd do this:

map(
    reduce (.tags[].value | split(":")) as [$k,$v] (
        del(.tags);
        .[$k] = $v
    )
)

Then as you access the fields, just use the alternative operator to set the default value.

(.domain // "-") as $domain