Original Query
SELECT DISTINCT
IP.op_code as ip_op_code,
IPH.op_code as iph_op_code,
debt_trans.tx_amount as cash,
DT.tx_amount as revenu
looking to your data could you join must match also for op_code AND instplanheader.op_code = instplan.op_code
$sql = "SELECT DISTINCT
instplan.debt_code,
instplan.op_code,
instplanheader.op_code as plan_op,
instplan.ipactualpaymentamt
FROM instplanheader
LEFT JOIN instplan ON instplanheader.debt_code=instplan.debt_code
AND instplanheader.op_code = instplan.op_code
AND instplan.tran_code NOT IN ('DR3001','DR3002','DR3003','DR3004')
AND instplan.ipactualpaymentamt > 0.00
AND instplan.ipactualpaymentdt >= '2019-02-04' AND instplan.ipactualpaymentdt <= '2019-02-04'
AND instplanheader.iphcreationdate >= '2018-12-01' AND instplanheader.iphcreationdate <= '2019-02-04'
";
This seems a touch nonsensical to me:
AND i.ipactualpaymentdt >= '2019-02-04'
AND i.ipactualpaymentdt <= '2019-02-04'
It means that your right table instplan
has multiple rows with the same debt_code
.
Let me show what I mean:
DECLARE @TestTable TABLE
(
Col1 VARCHAR(10),
Col2 INT,
Col3 INT
)
DECLARE @TestTable2 TABLE
(
Col1 VARCHAR(10),
Col2 VARCHAR(10),
Col3 VARCHAR(10)
)
INSERT INTO @TestTable
(
Col1,
Col2,
Col3
)
VALUES
('A', 10, 20)
INSERT INTO @TestTable2
(
Col1,
Col2,
Col3
)
VALUES
('A', 'A', 'A')
, ('A', 'B', 'B')
, ('A', 'C', 'C')
And query example:
SELECT
distinct t1.Col1 t1_Col
, t2.Col1 t2_Col1
, t2.Col2 t2_Col2
, t2.Col3 t2_Col3
FROM @TestTable t1
LEFT JOIN @TestTable2 t2 ON t2.Col1 = t1.Col1
Nevertheless, we see three rows althought we use DISTINCT keyword.
OUTPUT:
t1_Col t2_Col1 t2_Col2 t2_Col3
A A A A
A A B B
A A C C