extract part of a path with filename with php

Question

I need to extract a portion of urls using php. The last 6 segments of the url are the part I need. The first part of the url varies in length and number of directories. So if

Answer 1

Use this, substituting $url as you wish:

$url= "https://www.random.vov/part1/part2/part3/2016/08/file.pdf";
preg_match("%/[^/]*?/[^/]*?/[^/]*?/[^/]*?/[^/]*?/[^/]*?$%", $url, $matches);
echo $matches[0];

best regards!

Answer 2

Your approach is fine, though adding parse_url in there to isolate just the path will help a lot:

$path  = parse_url($url, PHP_URL_PATH); // just the path part of the URL
$parts = explode('/', $path);           // all the components
$parts = array_slice($parts, -6);       // the last six
$path  = implode('/', $parts);          // back together as a string

Try it online at 3v4l.org.

Now, to qualify: if you only need the string part of the path, then use parse_url. If, however, you need to work with each of the segments (such as removing only the last six, as asked), then use the common pattern of explode/manipulate/implode.

I have left each of these steps separate in the above so you can debug and choose the parts that work best for you.