modification of skipping empty list and continuing with function

Question

Background

The following code is slightly modified from skipping empty list and continuing with function

import pandas as pd
Names =             


        

Answer 1

Just add this line in the end fillna

df['New'].fillna(df['Text'],inplace=True)

Answer 2

@tawab_shakeel is close. Just add:

df['New'].fillna(df['Text'], inplace=True)

fillna will catch the correct value from df['Text'].

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I can also propose an alternative solution using the re module for regex.

def replacing(x):
    if len(x['P_Name']) > 0:
        return re.sub('|'.join(x['P_Name']), '**BLOCK**', x['Text'])
    else:
        return x['Text']

df['New'] = df.apply(replacing, axis=1)

The apply method applies the replacing function to each row, and substitution is done by the re.sub function.