Python for loop error

Question

I\'m working on a Python exercise at Codecademy and got stuck on what looks like a simple problem:

Write a function fizz_count() that loops t

Answer 1

If x is a sequence of elements, when you do

for i in x:

you are looping through the elements of x, not through indexes.

So when you do

x[i]

you are doing

x[element]

which makes no sense.

What can you do?

You can compare the element with 'fizz':

for element in x:
    if element == 'fizz':
        # ...

Answer 2

When you used { for i in x } then here 'i' is the item of the list and not an index. Hence,

Corrected Code is:

def fizz_count(x):
  count = 0
  for i in x:
    if i == 'fizz':
      count = count + 1
  return count

print fizz_count(['fizz', 'buzz'])

OUTPUT

1

Answer 3

You are passing in a list ['fizz', 'buzz']) so i is equal to fizz or buzz not an integer. Try if i =="fizz"

def fizz_count(x):
  count = 0
  for i in x:
    if i  == 'fizz': # i will be each element in your list
      count = count + 1
  return count