If statement runs through whether conditions are met or not

Question

My if statement runs through as if the conditions have been met even when they haven\'t. I have tried moving bits of code about and even rewriting the if statement differently b

Answer 1

This is really bogus

if (bob == "no", "No", "NO", "nO")

You need to break it out with logical OR instead

if (bob == "no" || bob == "No" || bob == "NO" || bob == "nO")

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As it stand, this if (bob == "no", "No", "NO", "nO") would be equivalent to if("nO") as the effect of the comma operator.

Answer 2

bob == "no", "No", "NO", "nO"

is not doing what you think it is doing. You mean to do:

bob == "no" ||
bob == "No" ||
bob == "NO" ||
bob == "nO"

Answer 3

This is a bit of a side note to your question, but in this context, you may want to consider converting the answer to lowercase (or uppercase) before comparing it.

That way, you can just use if (tolower(bob) == "no")

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Here's an example of how to do use the tolower function

http://www.cplusplus.com/reference/cctype/tolower/

/* tolower example */
#include <stdio.h>
#include <ctype.h>
int main ()
{
  int i=0;
  char str[]="Test String.\n";
  char c;
  while (str[i])
  {
    c=str[i];
    putchar (tolower(c));
    i++;
  }
  return 0;
}

Answer 4

Your loop problem can be explained:

while (continueBool = true)

should read

while (continueBool == true).

As your code currently stands, you are setting it to true instead of checking for a value, so it will never exit.