pointA=[9.62579 15.7309 3.3291];
pointB=[13.546 25.6869 3.3291];
pointC=[23.502 21.7667 -3.3291];
pointD=[19.5818 11.8107 -3.3291];
points=[pointA\' pointB\' pointC\'
clear all, close all, clc
pointA=rand(99,1);
pointB=rand(99,1);
pointC=rand(99,1);
pointD=rand(99,1);
pointAmat = reshape(pointA,3,1,[]);
pointBmat = reshape(pointB,3,1,[]);
pointCmat = reshape(pointC,3,1,[]);
pointDmat = reshape(pointD,3,1,[]);
points=[pointAmat pointBmat pointCmat pointDmat];
for i = 1:size(points,3)
fill3(points(1,:,i),points(2,:,i),points(3,:,i),'r')
hold all
end
grid on
alpha(0.3)
Hope this helps.
Assuming your data are a matrix, m = (400,3)
m = rand(400,3);
for i = 1:length(m);
m2 = m'; % Transpose
end
Create a 3-D matrix in which 'j' represents each set of points:
m3=[];
%Not the most elegant way to cycle through every four points but it works!
z = 0:(length(m2)/4); z1 = (z*4)+1; z1 = z1(:,1:length(z)-1);
for j = 1:length(z1);
m3(:,:,j) = m2(:,z1(j):(z1(j)+3));
end
'j' now has a total length = 100 - representing the amount planes;
fill3(m3(1,:,1),m3(2,:,1),m3(3,:,1),'r');
% Cycle through planes- make a new figure for each plane;
for j = 1:length(z1);
fill3(m3(1,:,j),m3(2,:,j),m3(3,:,j),'r');
end